A) \[3y=9x+2\]
B) \[y=2x+1\]
C) \[y=x+2\]
D) \[2y=x+8\]
Correct Answer: C
Solution :
\[y=mx+\frac{2}{m}\] Solved with \[xy=-1\] \[\therefore \,\,\,x\left( mx\,+\frac{2}{m} \right)\,=-1\] \[\Rightarrow \,\,{{x}^{2}}m+\frac{2}{m}\,x+1=0\] Put discriminanant = 0 \[\Rightarrow \,\,\frac{4}{{{m}^{2}}}=4m\,\Rightarrow \,m=1\,\,\,\therefore \,\,y=x+2\]
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