JEE Main & Advanced Sample Paper JEE Main Sample Paper-22

  • question_answer
    2 mol of \[{{N}_{2}}\]is mixed with 6 mol of \[{{H}_{2}}\] in a closed vessel of one litre capacity if 50% of \[{{N}_{2}}\] is converted into \[N{{H}_{3}}\]  at equilibrium, the ratio of \[\frac{{{K}_{f}}}{{{K}_{b}}}\] (rate constants) value of \[{{K}_{c}}\] for the reaction\[{{K}_{2(g)}}+3{{H}_{2(g)}}2N{{H}_{3(g)}}\] is :

    A)  \[\frac{4}{27}\]                        

    B)  \[\frac{27}{4}\]

    C)  \[\frac{1}{27}\]                        

    D)  24

    Correct Answer: A

    Solution :

    \[\underset{(a-x)}{\mathop{\overset{a}{\mathop{{{N}_{2}}}}\,}}\,+\underset{(b-3x)}{\mathop{\overset{b}{\mathop{3{{H}_{2}}}}\,}}\,\overset{0}{\mathop{\underset{(2x)}{\mathop{2N{{H}_{3}}}}\,}}\,\]50% Dissociation of \[{{N}_{2}}\] takes place so, At equilibrium \[\frac{2\times 50}{100};\] value of \[x=1\]


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