JEE Main & Advanced Sample Paper JEE Main Sample Paper-22

  • question_answer
    The compound that will react most readily with NaOH to form methanol is

    A)  \[{{(C{{H}_{3}})}_{4}}{{N}^{\oplus }}{{I}^{-}}\]              

    B)  \[C{{H}_{3}}-O-C{{H}_{3}}\]

    C)  \[{{(C{{H}_{3}})}_{3}}C-CI\]             

    D)  \[C{{H}_{3}}-I\]

    Correct Answer: A

    Solution :

    Reactivity increases with the leaving ability of leaving group increases, i.e., \[{{(C{{H}_{3}})}_{4}}{{N}^{\oplus }}>{{I}^{-}}>C{{l}^{-}}>OCH_{3}^{-}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner