2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-22

  • question_answer
    A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position, the knife are at a distance d from each other. The centre of mass of the rod is at distance \[x\]  from A. The normal reaction on A is:

    A)  \[\left( \frac{d-x}{d} \right)W\]               

    B)   \[\left( \frac{d}{d-x} \right)W\]

    C)  \[\left( \frac{d-x}{d+x} \right)W\]                       

    D)  \[\left( \frac{d+x}{d-x} \right)W\]

    Correct Answer: A

    Solution :

    \[{{\tau }_{B}}=0\Rightarrow {{N}_{A}}d=W(d-x)\,\Rightarrow \,{{N}_{A}}=\frac{W(d-x)}{d}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner