JEE Main & Advanced Sample Paper JEE Main Sample Paper-21

  • question_answer
    Two very long straight parallel wires carry steady currents \[I\] and \[-I\]respectively. The distance between wires is d. At a certain instant of time, a point charge q is at a point equidistant from two wires in the plane of the wires. Its instantaneous velocity \[\overrightarrow{v}\] is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is:                              

    A)  \[\frac{{{\mu }_{0}}Iqv}{2\pi d}\]                    

    B)  \[\frac{{{\mu }_{0}}Iqv}{\pi d}\]

    C)  \[\frac{2{{\mu }_{0}}Iqv}{\pi d}\]                    

    D)  zero

    Correct Answer: D

    Solution :

    The magnetic field due to both of the wires will downwards. \[\vec{F}=q\,(\vec{v}\times \vec{B})=0\] Since \[\vec{v}\] is parallel to \[\vec{B}\].


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