A) \[8\,gm.\]
B) \[16\,gm.\]
C) \[32\,gm.\]
D) None of these
Correct Answer: A
Solution :
Equivalent of \[Mo{{O}_{3}}=\frac{M}{6}=\frac{144}{6}=24\] equivalent of \[{{H}_{2}}:\frac{192}{24}=\frac{{{W}_{{{H}_{2}}}}}{1}\Rightarrow {{W}_{{{H}_{2}}}}=8gm.\]
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