JEE Main & Advanced Sample Paper JEE Main Sample Paper-20

  • question_answer
      A particle moves along x-axis with initial position \[x=0\]. Its velocity varies with x-coordinate as shown in graph. The acceleration 'a? of this particle varies with x as -            

    A)   

    B)  

    C)             

    D)  

    Correct Answer: A

    Solution :

     " The linear relationship between v and x is \[v=-mx+C\] where m and C are positive constants. \[\therefore \]  Acceleration, \[a=v\frac{dv}{dx}=-m(-mx+C)\] \[\therefore \] \[a={{m}^{2}}x-mC\] Hence the graph relating a to x is


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