A) the ionisation enthalpy of \[{{\text{N}}_{\text{2}}}\]gas is higher than that of \[{{\text{O}}_{\text{2}}}\] gas
B) the ionisation enthalpy of \[{{\text{N}}_{\text{2}}}\] gas is lower than that \[{{\text{O}}_{\text{2}}}\] gas
C) the ionisation enthalpy of\[{{\text{N}}_{\text{2}}}\] gas is higher than that of N atom
D) None of the above
Correct Answer: A
Solution :
lonization enthalpy of \[{{N}_{2}}\] gas (1503 kJ \[mo{{l}^{-1}}\]) is higher than that \[{{O}_{2}}\] gas (1175 kJ \[mo{{l}^{-1}}\]) and it cannot lose its electron so easily as \[{{O}_{2}}\] does informing \[O_{2}^{+}+{{[Pt{{F}_{6}}]}^{-}}\]compound.
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