JEE Main & Advanced Sample Paper JEE Main Sample Paper-1

  • question_answer
    An object is tossed vertically into the air with an initial velocity of 8 m/s. Using the sign convention up as positive, how does the vertical component of the acceleration ay of the object (after leaving the hand) vary during the flight of object?

    A) On the way up \[{{a}_{y}}>0,\]on the way down\[{{a}_{y}}>0\]

    B)  On the way up \[{{a}_{y}}>0,\] on the way down\[{{a}_{y}}<0,\]

    C)  On the way up \[{{a}_{y}}<0,\] on the way down\[{{a}_{y}}>0\]

    D)  On the way up \[{{a}_{y}}<0,\] on the way down\[{{a}_{y}}<0\]

    Correct Answer: D

    Solution :

    Since, acceleration acting on ball is only due to gravity, it would be in vertical downward direction and hence \[{{a}_{y}}<0\]for going up as well as when it is coming down. So, \[{{a}_{y}}<0\] for both.


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