| Statement-1: Range of\[f(x)=\sqrt{4-{{x}^{2}}}\]is\[[0,\,\,2]\]. |
| Statement-2: \[f(x)\] is increasing for \[0\le x\le 2\] and decreasing for\[-2\le x\le 0\]. |
A) Statement-1 is false, Statement-2 is true.
B) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
C) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
D) Statement-1 is true, Statement-2 is false.
Correct Answer: D
Solution :
\[f'(x)=\frac{-x}{\sqrt{4-{{x}^{2}}}}\] \[\therefore \]\[f(x)\]is increasing for \[-2\le x\le 0\] and decreasing for\[0\le x\le 2\].
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