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JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer
    \[\lambda \]for which \[\frac{x-2}{-3}=\frac{y-4}{7}=\frac{z-8}{\lambda }\] and\[\frac{x-1}{\lambda }=\frac{y-2}{-3}=\frac{z-3}{6}\] are perpendicular equals

    A) \[5\]                                     

    B) \[6\]

    C) \[7\]                                     

    D) \[8\]

    Correct Answer: C

    Solution :

     For perpendicularity\[-3\lambda -21+6\lambda =0\Rightarrow \lambda =7\].


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