A) \[\pi \]
B) \[\frac{\pi }{2}\]
C) \[\frac{\pi }{4}\]
D) None
Correct Answer: C
Solution :
\[\frac{2}{\cos 2\alpha }=\frac{{{\tan }^{2}}\beta +1}{\tan \beta }=\frac{1}{\sin \beta \cos \beta }\] \[\Rightarrow \]\[\sin 2\beta =\cos 2\alpha =\sin (90-2\alpha )\Rightarrow \alpha +\beta =\frac{\pi }{4}\]
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