JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer
    Select the rate law that corresponds to the data shown for the following reaction \[A+B\xrightarrow{{}}C\]
    Expt. No. (1) (2) Initial Rate
    1 \[0.012\] \[0.035\] \[0.10\]
    2 \[0.024\] \[0.070\] \[0.80\]
    3 \[0.024\] \[0.035\] \[0.10\]
    4 \[0.012\] \[0.070\] \[0.80\]

    A)  Rate \[=K{{[B]}^{3}}\]                              

    B)  Rate \[=K{{[B]}^{4}}\]

    C)  Rate \[=K[A]\,{{[B]}^{3}}\]

    D)  Rate \[=K{{[A]}^{2}}{{[B]}^{2}}\]

    Correct Answer: A

    Solution :

     Let the rate law be \[r={{[A]}^{x}}{{[B]}^{y}}\] Divide (3) by (1) \[\frac{0.10}{0.10}=\frac{{{[0.024]}^{x}}{{[0.035]}^{y}}}{{{[0.012]}^{x}}{{[0.035]}^{y}}}\] \[\therefore \] \[1={{[2]}^{x}},\,x=0\] Divide (2) by (3) \[\frac{0.80}{0.10}=\frac{{{[0.024]}^{x}}{{[0.070]}^{y}}}{{{[0.024]}^{x}}{{[0.035]}^{y}}}\] \[\therefore \]  \[8={{(2)}^{y}},\,\,y=3\] Hence rate equation, \[R=K{{[A]}^{0}}{{[B]}^{3}}=K{{[B]}^{3}}\]


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