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JEE Main & Advanced Sample Paper JEE Main Sample Paper-18

  • question_answer
    Two identical organ pipes are producing fundamental notes of frequencies 200 Hz at \[15{}^\circ C\]. If the temperature of one pipe is raised to \[27{}^\circ C\], the number of beats produced will be

    A)  2                                            

    B)  4

    C)  6                                            

    D)  8

    Correct Answer: B

    Solution :

     \[V\propto \sqrt{T}\] \[\frac{{{V}_{27}}}{{{V}_{15}}}=\sqrt{\frac{300}{288}}=1.02\] \[\therefore \]  \[\frac{n'}{n}=1.02\] \[\Rightarrow \]               \[n'=1.02\times 200=204\] No. of beats \[=204-200=4\]


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