A) \[mg\text{/}k\]
B) \[mg\text{/}\,\text{4}\,k\]
C) \[mg\text{/}\,\text{2}k\]
D) zero
Correct Answer: A
Solution :
When the elevator is stationary \[kx=mg\] \[\Rightarrow \] \[x=mg\text{/}k\] When the elevator falls with g, the apparent weight is zero. So, the equilibrium position corresponds to the natural length of the spring. So, amplitude\[=mg\text{/}k\]
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