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  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-18

  • question_answer
    Two conducting rings of radii \[r\] and 2\[r\] move in opposite directions with velocities 2\[v\] and \[v\] respectively on a conducting surface S. There is a uniform magnetic field of magnitude B perpendicular to the plane of the rings. The potential difference between the highest points of the two rings is

    A)  zero                     

    B)  \[2\,\,rvB\]

    C)  \[4\,\,rvB\]                       

    D)  \[8\,\,rvB\]

    Correct Answer: D

    Solution :

     \[{{V}_{M}}-{{V}_{P}}=2\,r\cdot B\cdot 2v=4Brv\] \[{{V}_{Q}}-{{V}_{n}}=4r\cdot B\cdot v=4Brv\] But, \[{{V}_{P}}={{V}_{Q}}\] \[\therefore \]  \[{{V}_{M}}-{{V}_{N}}=\,8\,Brv\]


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