JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    Runs scored by a batsman in 10 innings are: 38, 70,48, 34,42, 55, 63,46, 54 and 44. The mean deviation is

    A)  8.6                        

    B)  6.4

    C)  10.6                      

    D)  9.6

    Correct Answer: A

    Solution :

     Arranging the given data in ascending order, we have \[34,38,42,44,46,48,54,55,63,70\] Here median, \[M=\frac{46+48}{2}=47\] [Because \[n=10\]and median is the mean of 5th and 6th terms] \[\therefore \]mean deviation \[=\frac{\sum{|{{x}_{i}}-M|}}{n}=\frac{\sum{|{{x}_{i}}-47|}}{10}\] \[=\frac{13+9+5+3+1+1+7+8+16+23}{10}\] \[=8.6\]


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