A) 3/2
B) 0
C) 1
D) \[\pm \,1\]
Correct Answer: D
Solution :
A line parallel to the \[y-\]axis has the slope \[\infty .\] Thus, \[({{a}^{2}}-1){{m}^{2}}-(2a-3)m+a=0\]must have one infinite root. \[\therefore \]\[{{a}^{2}}-1=0\](\[\because \]both roots cannot be\[\infty \]then \[{{a}^{2}}-1\]) \[=0,2a-3=0\]are to hold for the same a)
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