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JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    Solution of the equation \[\frac{dy}{dx}=\frac{3y{{x}^{2}}}{{{x}^{3}}+2{{y}^{4}}}\]is

    A)  \[{{x}^{3}}{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]     

    B) \[{{x}^{2}}{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]

    C)  \[x{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]    

    D)  None of these

    Correct Answer: A

    Solution :

     \[(3y{{x}^{2}})dx+(-{{x}^{3}}-2{{y}^{4}})\,dy=0\] Integrating, we get \[{{x}^{3}}{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]


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