JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    \[{{\text{I}}_{\text{2}}}\]and\[\text{B}{{\text{r}}_{\text{2}}}\]are added to a solution containing\[{{\text{I}}^{-}}\]  and \[\text{B}{{\text{r}}^{-}}.\]What reaction would occur if  \[E_{{{I}_{2}}/{{I}^{-}}}^{o}=+\,0.54\,V\]and \[E_{B{{r}_{2}}/B{{r}^{-}}}^{o}=+1.09\,V?\]

    A) \[{{I}_{2}}+2B{{r}^{-}}\to B{{r}_{2}}+2{{I}^{-}}\]

    B)  \[B{{r}_{2}}+2{{I}^{-}}\to 2B{{r}^{-}}+{{I}_{2}}\]

    C)  \[{{I}_{2}}+2B{{r}^{-}}\to IB{{r}_{2}}+{{I}^{-}}\]

    D)  \[{{I}_{2}}+B{{r}_{2}} & \to 2IBr\]

    Correct Answer: B

    Solution :

     This reaction will be occurred (that cell reaction is possible in which cathode is of higher reduction potential). \[B{{r}_{2}}+2{{I}^{-}}\xrightarrow{{}}2B{{r}^{-}}+{{I}_{2}}\] because,\[E_{Cell}^{o}=\text{positive}\] \[=E_{B{{r}_{2}}/B{{r}^{-}}}^{o}+E_{{{I}^{-}}/{{I}_{2}}}^{o}\] \[=1.09-0.54=0.55\]


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