JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    A compound XY crystallizes in BCC lattice with unit cell-edge length of 480 pm. If the radius of \[{{Y}^{-}}\]is 225 pm, then the radius of \[{{X}^{+}}\] is

    A)  190.70 pm         

    B)  225 pm

    C)  127.5pm             

    D)  None of these

    Correct Answer: A

    Solution :

     For BCC lattice, \[\sqrt{3}a=2({{r}^{+}}+{{r}^{-}})\] \[\Rightarrow \]\[{{r}^{+}}+{{r}^{-}}=\frac{\sqrt{3}}{2}a\] \[\Rightarrow \]\[{{r}^{+}}+{{r}^{-}}=\frac{\sqrt{3}}{2}\times 480\] \[\Rightarrow \]\[{{r}^{+}}=\frac{\sqrt{3}}{2}\times 480-{{r}^{-}}\] \[\Rightarrow \]\[{{r}^{+}}=415.68-225\] \[\Rightarrow \]\[{{r}^{+}}=190.68\,pm\]


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