JEE Main & Advanced Sample Paper JEE Main Sample Paper-16

  • question_answer
    A 600 W carrier wave is modulated to a depth of 75% by a 400Hz sine wave. Find the total antenna power.

    A)  769 W                                  

    B)  796 W

    C)  679 W                                  

    D)  637.5 W

    Correct Answer: A

    Solution :

    \[{{P}_{T}}={{P}_{C}}\left( 1+\frac{{{m}^{2}}}{2} \right)=600\left( 1+\frac{9}{32} \right)=600\times \left( \frac{41}{32} \right)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner