JEE Main & Advanced Sample Paper JEE Main Sample Paper-16

  • question_answer
    Masses of neutron, proton and electron are 1.0087 U, 1.0073 u and 0.0005 u respectively. If a neutron decays into a proton and an electron, the energy released would be about

    A)  0.68 MeV           

    B)  0.84 MeV

    C)  0.75 MeV           

    D)  1.22 MeV

    Correct Answer: B

    Solution :

    \[_{0}^{1}n\to _{1}^{1}p+_{-1}^{0}e\] \[Q=({{m}_{n}}-{{m}_{p}}-{{m}_{e}}){{c}^{2}}\] \[=0.0009\times 931.5\]


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