JEE Main & Advanced Sample Paper JEE Main Sample Paper-16

  • question_answer
    Equation of a longitudinal wave is given as \[y={{10}^{-2}}\sin 2\pi \left( 1000t+\frac{50x}{17} \right)\] (all SI units). At t = 0, change in pressure is maximum (in modulus) at \[x=\]

    A)  0.34                                      

    B)  0.255

    C)  0.085                                   

    D)  All of these

    Correct Answer: A

    Solution :

    \[p=\frac{-B\partial S}{\partial x}=-{{10}^{-2}}B\times 2\pi \cos (2000\pi t+\]\[\frac{1000\pi x}{17})\]\[\times \frac{50}{17}\]Maximum when\[\cos \left( \frac{1000\pi x}{17} \right)=+1\]


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