question_answer

A particle executes SHM between \[x=-A\] to \[x=+A\]. The time taken for it to go from 0 to \[\frac{\text{A}}{\text{2}}\] is \[{{\text{T}}_{\text{1}}}\]and to go from \[\frac{\text{A}}{\text{2}}\] to A is \[{{\text{T}}_{\text{2}}}\]then \[\frac{{{\text{T}}_{\text{1}}}}{{{\text{T}}_{\text{2}}}}\]is

A)  2                                            

B) \[\frac{1}{2}\]

C)  4                                            

D) \[\frac{1}{4}\]

Correct Answer: B

Solution :

\[\omega {{T}_{1}}=\frac{\pi }{6}\] \[\omega {{T}_{2}}=\frac{\pi }{3}\] \[\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\frac{1}{2}\]