JEE Main & Advanced Sample Paper JEE Main Sample Paper-15

  • question_answer
    If\[\underset{n\to \infty }{\mathop{\lim }}\,\frac{{{l}^{a}}+{{2}^{n}}+{{3}^{a}}+...+{{n}^{a}}}{{{n}^{a+1}}}=\frac{1}{5},\] (where \[a>-1\]) then the value of 'a' is

    A)  2                                            

    B)  3

    C)  4                                            

    D)  5

    Correct Answer: C

    Solution :

    \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{1}{n}\left( {{\left( \frac{1}{n} \right)}^{a}}+{{\left( \frac{2}{n} \right)}^{a}}+....+{{\left( \frac{n}{n} \right)}^{a}} \right)\] \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{1}{n}\sum\limits_{r=1}^{n}{{{\left( \frac{r}{n} \right)}^{a}}}\]\[\int\limits_{0}^{1}{{{x}^{a}}dx=\frac{1}{a+1}=\frac{1}{5}}\]\[a=4\] ans.


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