A) 0
B) 1
C) 4 sin 5
D) 4 sin 25
Correct Answer: D
Solution :
\[f'(x)=\sin {{x}^{2}}\]\[y=f({{x}^{2}}+1)\] \[\frac{dy}{dx}=f'({{x}^{2}}+1)\cdot 2x\] \[{{\left. \frac{dy}{dx} \right|}_{x=2}}=4f'(5)=4\sin 25.\]You need to login to perform this action.
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