JEE Main & Advanced Sample Paper JEE Main Sample Paper-15

  • question_answer
    If real numbers \[p,\,q,\,r\] satisfy \[4p+3q+r=7,\] then the least value of \[(2{{p}^{2}}+{{q}^{2}}+{{r}^{2}})\] is

    A) \[\sqrt{7}\]                                        

    B) \[\frac{7}{\sqrt{2}}\]

    C) \[\frac{\sqrt{7}}{2}\]                                     

    D) \[\frac{49}{18}\]

    Correct Answer: D

    Solution :

    \[\left( \sqrt{2}a\hat{i}+b\hat{j}+c\hat{k} \right).\left( 2\sqrt{2}\hat{i}+3\hat{j}+\hat{k} \right)\] \[=\sqrt{2{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}\sqrt{18}\cos \theta .\] \[{{\left( \sqrt{2{{a}^{2}}+{{b}^{2}}+{{c}^{2}}} \right)}_{\min .}}=\frac{7}{3\sqrt{2}};\] when\[\cos \theta =1\]. \[\therefore \]\[{{(2{{a}^{2}}+{{b}^{2}}+{{c}^{2}})}_{\min .}}=\frac{49}{18}.\]


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