JEE Main & Advanced Sample Paper JEE Main Sample Paper-15

  • question_answer
    Two long parallel straight conductors carry current \[{{\text{i}}_{\text{1}}}\], and \[{{\text{i}}_{2}}\]\[\text{(}{{\text{i}}_{1}}>{{\text{i}}_{\text{2}}}).\]When the currents are in the same direction, the magnetic field at a point midway between the wires is \[20\mu T\]. If the direction of \[{{\text{i}}_{\text{2}}}\]is reversed, the field becomes \[50\mu T\]. The ratio of the currents \[{{\text{i}}_{1}}\text{/}{{\text{i}}_{\text{2}}}\]is:

    A)  5/2                                       

    B)  7/3

    C)  4/3                                       

    D)  5/3

    Correct Answer: B

    Solution :

    \[B=\frac{{{\mu }_{0}}}{2\pi (d/2)}({{i}_{1}}-{{i}_{2}})=20\] \[B=\frac{{{\mu }_{0}}}{2\pi (d/2)}({{i}_{1}}+{{i}_{2}})=50\] \[\frac{{{i}_{1}}-{{i}_{2}}}{{{i}_{1}}+{{i}_{2}}}=\frac{2}{5}\]Treading\[\frac{{{i}_{1}}}{{{i}_{2}}}=x\]\[x=\frac{7}{3}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner