A) \[{{[PbC{{l}_{4}}]}^{2-}}\]
B) \[{{[Ni\,{{(CN)}_{4}}]}^{2-}}\]
C) \[{{[Pb\,{{(CN)}_{4}}]}^{2-}}\]
D) \[{{[NiC{{l}_{4}}]}^{2-}}\]
Correct Answer: D
Solution :
Only \[{{[NiC{{l}_{4}}]}^{2-}}\] has tetrahedral structure while others show square planar structure. This is because of the involvement of \[s{{p}^{3}}\] hybridised orbital as \[C{{l}^{-}}\] is weak field ligand (hence, \[(n-1)\] orbitals of Ni are not available for overlapping).
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