Direction: (Q. Nos. 85) Let \[\frac{dy}{dx}=\frac{1}{x+y}\,\] and \[y(0)=0\]. Then |
A) \[\frac{1}{2}\]
B) \[\frac{e}{2}\]
C) \[e-\frac{1}{2}\]
D) \[e-\frac{5}{2}\]
Correct Answer: D
Solution :
\[\int_{0}^{1}{x\,\,dy}=\,\int_{0}^{1}{({{e}^{y}}-y-1)\,dy}\] \[=\left( {{e}^{y}}-\frac{{{y}^{2}}}{2}-y \right)_{0}^{1}\] \[=e-\frac{5}{2}\]You need to login to perform this action.
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