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JEE Main & Advanced Sample Paper JEE Main Sample Paper-13

  • question_answer
    \[\sum\limits_{r=1}^{20}{\,\sum\limits_{p\,=\,1}^{r}{{{p}^{2}}}}\] is equal to 

    A)  16170                  

    B)  13300          

    C)  16100                                  

    D)  None of these

    Correct Answer: A

    Solution :

     \[\frac{0.024-{{p}_{S}}}{{{p}_{S}}}=\frac{68.4}{342}\times \frac{18}{1000}\] \[\therefore \] \[{{p}_{S}}=0.0239\,atm\] \[\Delta {{T}_{f}}={{K}_{f}}m\]


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