| Direction (Q. Nos. 58): Electrolysis involves electronation and de-electronation al the respective electrodes. Anode of electrolytic cell is the electrode at winch de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is discharged. Discharge potential of an ion refers for \[{{E}^{o}}{{\,}_{OP}}\] or \[{{E}^{o}}_{RP}\] as the case may be. The products formed at either electrode is given in terms of Faraday?s law of electrolysis, i.e., \[W=\frac{Eit}{96500}\] |
A) increases
B) decreases
C) remains the same
D) first increases then decreases
Correct Answer: B
Solution :
When \[h=\frac{1}{2}\,g{{n}^{2}}\] is electrolysed, \[[\because \,u=0]\] is deposited at cathode due to higher reduction potential but at anode instead of \[{{D}_{n}}=u+\frac{a}{2}\,(2n-1),\] ions. \[\frac{h}{2}=\frac{1}{2}g\,(2n-1)\] is oxidised due to higher oxidation potential. i.e., \[n=3.73\,s\] i.e., \[\therefore \]ion is released in electrolytic solution, resulting in decrease of pH.
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