A) dehydration
B) hydration
C) hydrolysis
D) reduction
Correct Answer: C
Solution :
Hydrolysis of \[{{K}_{R}}=\frac{1}{2}I{{\omega }^{2}}=\frac{1}{5}m{{r}^{2}}{{\omega }^{2}}\] gives \[\frac{{{K}_{R}}}{K}=\frac{\frac{1}{5}m{{r}^{2}}{{\omega }^{2}}}{\frac{7}{10}m{{r}^{2}}{{\omega }^{2}}}=\frac{2}{7}\] which fumes in air. \[\therefore \]
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