JEE Main & Advanced Sample Paper JEE Main Sample Paper-13

  • question_answer
    A system is taken from state A to state B along two different paths 1 and 2. The work done on the system along these two paths are \[{{W}_{1}}\] and \[{{W}_{2}}\], respectively. The heat absorbed by the system along these two paths are \[{{Q}_{1}}\] and \[{{Q}_{2}}\], respectively. The internal energies at A and B are \[{{U}_{A}}\] and \[{{U}_{B}}\] respectively. Then,

    A)  \[{{W}_{1}}={{W}_{2}}={{U}_{B}}-{{U}_{A}}\]

    B)  \[{{Q}_{1}}-{{Q}_{2}}={{U}_{A}}-{{U}_{B}}\]

    C)  \[{{Q}_{1}}+{{W}_{1}}={{Q}_{2}}+{{W}_{2}}={{U}_{A}}+{{U}_{B}}\]

    D)  \[{{Q}_{1}}+(-{{W}_{1}})={{Q}_{2}}+(-{{W}_{2}})={{U}_{B}}-{{U}_{A}}\]

    Correct Answer: D

    Solution :

     By first law of thermodynamics, \[2HCO{{O}^{\odot -}}\xrightarrow{\,}\,2HCO{{O}^{\bullet }}+2{{e}^{-}}\]


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