JEE Main & Advanced Sample Paper JEE Main Sample Paper-13

  • question_answer
    If the velocity v of a particle moving along a straight line decreases linearly with its displacement S from \[20\,\,m{{s}^{-1}}\] to a value approaching zero at \[S=30\,m\], then acceleration of the particle at \[S=15\,m\], is

    A)  \[\frac{2}{3}\,m{{s}^{-2}}\]                        

    B)  \[-\frac{2}{3}\,m{{s}^{-2}}\]

    C)  \[\frac{20}{3}\,m{{s}^{-2}}\]                     

    D)  \[-\frac{20}{3}\,m{{s}^{-2}}\]

    Correct Answer: D

    Solution :

     Slope of line \[A{{l}_{2}}{{S}_{3}}+6{{H}_{2}}O\xrightarrow{\,}\,2Al{{(OH)}_{3}}+3{{H}_{2}}S\] Equation of line is \[M{{g}^{2+}}\] \[A{{l}^{3+}}\] \[=2\times 4=8\] Velocity of \[\therefore \] m. i.e.. \[=\frac{1}{8}\times 100\] Differentiating Eq. (i) w.r.t. time, Acceleration \[AlC{{l}_{3}}\] \[HCl\] \[AlC{{l}_{3}}+3{{H}_{2}}O\xrightarrow{\,}\,Al{{(OH)}_{3}}+3HCl\]


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