question_answer

In the LC circuit, the current in the direction shown and the charges on the capacitor plates have the signs shown. At this time

A)  I is increasing and Q is increasing

B)  I is increasing and Q is decreasing

C)   I is decreasing and Q is increasing

D)  I is decreasing and Q is decreasing

Correct Answer: B

Solution :

As it can be easily seen by the direction of I that Q is decreasing thus, energy of capacitor is decreasing and hence, energy of inductance is increasing or \[\left( \frac{\text{1}}{\text{2}}\text{L}{{\text{I}}^{\text{2}}} \right)\] gives that I is increasing.