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JEE Main & Advanced Sample Paper JEE Main Sample Paper-12

  • question_answer
    When an isolated gaseous cation \[{{X}^{+}}(g)\] is converted into \[{{X}^{-}}(g)\] anion, the amount of energy released is 16.8eV. Calculate the electro negativity value of the atom X on Pauling's scale.

    A)  1                                            

    B)  2

    C)  4                                            

    D)  3

    Correct Answer: D

    Solution :

     \[{{X}^{+}}(g)\xrightarrow[{}]{{}}{{X}^{-}}(g);\]Energy \[=IE+IA=16.8\,\text{eV}\] \[E{{N}_{pauling}}=\frac{IA+EA}{5.6}=\frac{16.8}{5.6}=3\]


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