JEE Main & Advanced Sample Paper JEE Main Sample Paper-12

  • question_answer
    Match List I (Molecules) with List II (Bond order) and select the correct answer using the codes
    List-I List-II
    I \[\text{L}{{\text{i}}_{\text{2}}}\] A. 3
    II \[{{\text{N}}_{\text{2}}}\] B. 1.5
    III \[\text{B}{{\text{e}}_{\text{2}}}\] C. 1.0
    IV \[{{\text{O}}_{\text{2}}}\] D. 0
    E. 0
    Codes:

    A)  \[\text{I-B,II-C,III-A,IV-E}\]       

    B)  \[\text{I-C,II-A,III-D,IV-E}\]

    C)  \[\text{I-D,II-A,III-E,IV-C}\]

    D)  \[\text{I-C,II-B,III-E,IV-A}\]

    Correct Answer: B

    Solution :

     \[B.O.={\scriptstyle{}^{1}/{}_{2}}[{{N}_{b}}-{{N}_{a}}]\] \[L{{i}_{2}}=\frac{4-2}{2}=1;{{N}_{2}}=3;Be=0,{{O}_{2}}=2.\]


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