JEE Main & Advanced Sample Paper JEE Main Sample Paper-11

  • question_answer
    What mass of \[{{H}_{2}}(g)\]is needed to reduce 192gm. of \[Mo{{O}_{3}}\] to metal? [At. wt. of Mo = 96]

    A)  8 gm.                   

    B)  16 gm.

    C)  32 gm.                 

    D)  None of these

    Correct Answer: A

    Solution :

     Equivalent of \[Mo{{O}_{3}}=\frac{M}{6}=\frac{144}{6}=24\] Equivalent of \[{{H}_{2}}:\frac{192}{24}=\frac{{{W}_{{{H}_{2}}}}}{1}\Rightarrow {{W}_{{{H}_{2}}}}=8gm.\]


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