A) \[\frac{Q{{E}_{0}}}{m{{\omega }^{2}}}\]
B) \[\frac{1}{2}\frac{Q{{E}_{0}}}{m{{\omega }^{2}}}\]
C) \[\frac{2Q{{E}_{0}}}{m{{\omega }^{2}}}\]
D) None of these
Correct Answer: A
Solution :
For a particle undergoing SHM with an amplitude A and angular frequency \[\omega ,\] the maximum acceleration \[={{\omega }^{2}}\text{A}\] Here the maximum force on the particle \[=Q{{E}_{0}}\] \[\therefore \]maximum acceleration \[=\frac{Q{{E}_{0}}}{m}={{\omega }^{2}}A\] \[\therefore \]\[A=\frac{Q{{E}_{0}}}{m{{\omega }^{2}}}\]
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