A) 2-butanal
B) 3-hydroxy butanal
C) 3-formyl-2-propanol
D) 4-oxo-2-propanpl
Correct Answer: B
Solution :
\[HC\equiv CH\xrightarrow[{{H}_{2}}S{{O}_{4}}]{HgS{{O}_{4}}}C{{H}_{3}}-CHO\xrightarrow[{}]{aldol}\] \[\text{C}{{\text{H}}_{\text{3}}}\text{-}\underset{\text{3}}{\overset{\begin{smallmatrix} \text{OH} \\ \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{CH}}}}\,\text{-}\underset{\text{2}}{\mathop{\text{C}}}\,{{\text{H}}_{\text{2}}}\text{-}\underset{\text{1}}{\mathop{\text{C}}}\,\text{HO}\] (3-hydroxy butanal)
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