JEE Main & Advanced Sample Paper JEE Main Sample Paper-11

  • question_answer
    pH of the solution: \[\left( \begin{align}   & \text{10}\,\underset{+}{\mathop{\text{litre}\,}}\,\text{of}\,\text{0}\text{.03}\,\text{NX}\,{{\text{(OH)}}_{\text{2}}}\text{(strong}\,\text{diacidic}\,\text{base)} \\  & \text{5}\,\text{litre}\,\text{of}\,\text{0}\text{.08}\,\text{M}\,\text{HN}{{\text{O}}_{\text{3}}} \\  & \text{485}\,\overset{+}{\mathop{\text{litre}}}\,\,\text{of}\,\text{0}\text{.01}\,\text{M}\,\text{NaN}{{\text{O}}_{\text{3}}} \\ \end{align} \right)\]

    A)  3.7                        

    B)  11.0

    C)  7.0                        

    D)  10.0

    Correct Answer: A

    Solution :

     \[{{[{{H}^{+}}]}_{remaining}}=\frac{5\times 0.08-10\times 0.03}{10+5+485}=2\times {{10}^{-4}}\]? \[pH=3.7\]


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