JEE Main & Advanced Sample Paper JEE Main Sample Paper-11

  • question_answer
    At certain temperature (T) if conductivity of pure water is \[5.5\times {{10}^{-7}}S\,c{{m}^{-1}},\]then calculate pOH of pure water at temperature T. Given \[\lambda _{{{H}^{+}}}^{\infty }=350\,S\,c{{m}^{2}}e{{q}^{-1}},\] \[\lambda _{O{{H}^{-}}}^{\infty }=200\] \[\,S\,c{{m}^{2}}e{{q}^{-1}}\]

    A)  5                                            

    B)  6

    C)  7                                            

    D)  8

    Correct Answer: B

    Solution :

     \[\wedge _{{{H}_{2}}O}^{\infty }=\frac{k\times 1000}{N},N=\frac{5.5\times {{10}^{-7}}\times 1000}{550}={{10}^{-6}}\] \[{{K}_{w}}={{N}^{2}}\]or \[{{M}^{2}},pH=pOH=6\]


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