2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-10

  • question_answer
    The coordinates of the point on the parabola y2 = 8x, which is at minimum distance from circle x2 + (y - 6)2 = 1 are

    A)  (2, 14)                 

    B)  (12,18)               

    C)  (2, 4)                    

    D)  (4, 2)

    Correct Answer: C

    Solution :

     Here, the minimum distance occur along the common normal. Any normal to y2 = 8 x at\[(2{{t}^{2}},4t)\]is\[tx+y=4t+2{{t}^{3}}\] It passes through the centre (0, 6) of the circle \[6=4t+2{{t}^{3}}\Rightarrow t=1\]So, required points (2, 4).


You need to login to perform this action.
You will be redirected in 3 sec spinner