A) which combines with\[{{H}_{2}}S{{O}_{4}}\]to give a very strong oxidising mixture and oxidises Cu to\[C{{u}^{2+}}\]
B) to oxidise Cu to\[C{{u}^{2+}}\]which then form\[CuS{{O}_{4}}\]with dilute\[{{H}_{2}}S{{O}_{4}}\]
C) to increase ionization of\[{{H}_{2}}S{{O}_{4}}\]to give\[SO_{4}^{2-}\]ions
D) to oxidize\[F{{e}^{2+}}\]to\[F{{e}^{3+}}\]sulphate, which remains in solution after crystallisation of\[CuS{{O}_{4}}\]
Correct Answer: D
Solution :
\[FeS{{O}_{4}}\xrightarrow[HN{{O}_{3}}]{\text{Dilute}}\underset{\text{remains in solution}}{\mathop{F{{e}_{2}}{{(S{{O}_{4}})}_{3}}}}\,\downarrow +CuS{{O}_{4}}\] crystallises out.
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