question_answer

Area bounded by the curve and \[x=0\] is

A) \[\frac{3}{4}\]                       

B) \[\frac{3}{2}\]         

C) \[\frac{3}{8}\]                      

D) \[3\]

Correct Answer: B

Solution :

[b] Required area \[=2\int\limits_{0}^{1}{\left[ (2-x)-{{x}^{1/3}} \right]}dx\] \[=2\left[ 2x-\frac{{{x}^{2}}}{2}-\frac{3{{x}^{4/3}}}{4} \right]_{0}^{1}=2\left[ 2-\frac{1}{2}-\frac{3}{4} \right]=\frac{3}{2}\]