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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 9

  • question_answer
    The melting point of RbBr is \[682{}^\circ C\], while that of NaF is \[988{}^\circ C\]. The melting point of NaF is much higher than that of RbBr because

    A)  the two crystals are not isomorphous

    B)  the molar mass of NaF is smaller than that of RbBr

    C)  the intern clear distance, \[{{r}_{c}}+{{r}_{a}}\]is greater for RbBr than for NaF

    D)  the bond in RbBr has more covalent character than the bond in NaF.

    Correct Answer: C

    Solution :

    [c] : This leads to stronger coulombic forces of attractions in NaR


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