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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 9

  • question_answer
    Taking the wavelength of first Balmer line in hydrogen spectrum (\[n=3\] to \[n=2\]) as \[660\text{ }nm,\] the wavelength (in nm) of the 2nd Balmer line (\[n=4\] to \[n=2\]) will be;       

    Answer:

    488.9


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