A) \[\frac{1}{5}\]
B) \[\frac{1}{3}\]
C) \[\frac{3}{2}\]
D) \[\frac{2}{3}\]
Correct Answer: D
Solution :
[d]: Maximum amplitude,\[{{A}_{\max }}={{A}_{c}}+{{A}_{m}}\] ...(i) Minimum amplitude, \[{{A}_{\min }}={{A}_{c}}-{{A}_{m}}\] ...(ii) Solving (i) and (ii), we get \[{{A}_{c}}=\frac{{{A}_{\max }}+{{A}_{\min }}}{2},{{A}_{m}}=\frac{{{A}_{\max }}-{{A}_{\min }}}{2}\] Modulation index, \[\mu =\frac{{{A}_{m}}}{{{A}_{c}}}=\frac{{{A}_{\max }}-{{A}_{\min }}}{{{A}_{\max }}+{{A}_{\min }}}\] \[\mu =\frac{25V-5V}{25V+5V}=\frac{20}{30}=\frac{2}{3}\]
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